Home
Archaeology
Astronomy
Biology
Books
Business
Chemistry
Coins
Computers
Conservation
Cooking
Earth Science
Farming
Economics
Finance
Games
Geography
Health Science
History by Date
Hobbies
Law
Mathematics
Medicine
Military Technology
Movies
Music
People
Pharmacology
Philosophy
Physics
Psychology
Religion
Science History
Technology
Sports
Television
Video
Visual Art
Privacy
Contact Us



Proof of angular momentum

A proof that torque is equal to the time-derivative of angular momentum can be stated as follows:

The definition of angular momentum for a single particle is:

L = r × p

where "×" indicates the vector cross product. The time-derivative of this is:

dL/dt = r × (dp/dt) + (dr/dt) × p

This result can easily be proven by splitting the vectors into components and applying the product rule. Now using the definitions of velocity v = dr/dt, acceleration a = dv/dt and linear momentum p = ma, we can see that:

dL/dt = r × m (dv/dt) + mv × v

But the cross product of any vector with itself is zero, so the second term vanishes. Hence with the definition of force F = ma, we obtain:

dL/dt = r × F

And by definition, torque τ = r×F. Note that there is a hidden assumption that mass is constant — this is quite valid in non-relativistic mechanics. Also, total (summed) forces and torques have been used — it perhaps would have been more rigorous to write:

dL/dt = τtot = ∑i τi

Copyright 2004. All rights reserved.